16*x^2-80*x+30=0

Solution for 16*x^2-80*x+30=0 equation:

16x^2-80x+30=0

a = 16; b = -80; c = +30;
Δ = b2-4ac
Δ = -802-4·16·30
Δ = 4480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4480}=\sqrt{64*70}=\sqrt{64}*\sqrt{70}=8\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-8\sqrt{70}}{2*16}=\frac{80-8\sqrt{70}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+8\sqrt{70}}{2*16}=\frac{80+8\sqrt{70}}{32}
$